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Solve the following system of linear equations using elimination. 3x+y=10 4x-y=4

User Aung
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We have


\begin{gathered} 3x+y=10 \\ 4x-y=4​ \end{gathered}

we will use the elimination method to sum the first equation with the second equation


\begin{gathered} 3x+4x+y-y=10+4 \\ 7x=14 \end{gathered}

then we can isolate the x


\begin{gathered} x=(14)/(7) \\ x=2 \end{gathered}

then we substitute the value of x in the first equation in order to find y


3(2)+y=10

we isolate the y


\begin{gathered} y=10-6 \\ y=4 \end{gathered}

the solution is x=2, y=4

User Joseph Tura
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