Question

Solve the following quadratic equation for complex solutions 3x^2- 7x + 11 = 0

Answer 1

To find the answer to this question, we have to use the quadratic formula:

`x=(-b^\pm√(b^2-4ac))/(2a)`

In this case, a has a value of 3, b has a value of -7 and c has a value of 11, replace for the given values:

`\begin{gathered} x=(-(-7)^\pm√((-7)^2-4(3)(11)))/(2(3)) \\ x=(7\pm√(49-132))/(6) \\ x=(7\pm√(-83))/(6) \\ x=(7\pm√(83)i)/(6) \\ x1=(7+√(83)i)/(6) \\ x2=(7-√(83)i)/(6) \end{gathered}`

It means that the solutions of the equation are (7+√83i)/6 and (7-√83i)/6