Question

150. g of aluminum chloride in 0.450 liters of solution, what is the concentration? (any examples are helpful, thank you)

Answer 1

2.49 M

Step-by-step explanation:

Step 1: Given data

• Mass of AlCl₃: 150. g

• Volume of solution: 0.450 L

Step 2: Calculate the moles AlCl₃ (solute)

The molar mass of AlCl₃ is 133.34 g/mol.

150. g × 1 mol/133.34 g = 1.12 mol

Step 3: Calculate the molar concentration of AlCl₃

Molarity is equal to the moles of solute divided by the liters of solution.

M = 1.12 mol/0.450 L = 2.49 M