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The slope of the tangent to a curve at any point (x, y) on the curve is negative x divided by y . Find the equation of the curve if the point (2, -2) is on the curve. x + y = 0 x^2 - y^2 = -2 x^2 + y^2
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9 votes
9 votes
The slope of the tangent to a curve at any point (x, y) on the curve is negative x divided by y . Find the equation of the curve if the point (2, -2) is on the curve.

x + y = 0
x^2 - y^2 = -2
x^2 + y^2 = 16
x^2 + y^2 = 8

User Webeng
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3.4k points

2 Answers

27 votes
27 votes

Answer:

.

Explanation:

.

User Hwen
by
2.8k points
12 votes
12 votes

Answer:

i belive its x^2 + y^2 = 8

Explanation:

User Muglio
by
3.4k points
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