Question

I need help re writing the angles as the inverse.

Answer 1

The Solution:

Given:

Find angle 1 and angle 2.

By Trigonometric Ratio:

Step 1:

`\begin{gathered} \sin\angle1=(opposite)/(hypotenuse) \\ \\ \sin\angle1=(3)/(5) \\ By\text{ inverse Trig ratio,} \\ \angle1=\sin^(-1)((3)/(5))=36.87^o \end{gathered}`

Step 2:

`\begin{gathered} \sin\angle2=(4)/(5) \\ \\ By\text{ inverse Trig. Ratio,} \\ \\ \angle2=\sin^(-1)((4)/(5))=53.13^o \end{gathered}`

Therefore, the correct answers are:

`\begin{gathered} \angle1=36.87^o \\ \\ \angle2=53.13^o \end{gathered}`