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A house that is 12 feet tall casts a shadow that is 10 feet long. How long would the shadow be for a house that is 18 feet tall?

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Answer: 15

"5/6 of 18 is 15", put that.

User Taye
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\begin{gathered} \text{the angle is the same in both cases} \\ \text{For the 12 f}eet\text{ tall} \\ \tan (\theta)=(tall)/(shadow)=(12)/(10)=1.2 \\ \text{For the 18 fe}et\text{ tall} \\ \tan (\theta)=(tall)/(shadow) \\ \text{shadow}=(tall)/(\tan (\theta)) \\ \text{shadow}=(18)/(1.2) \\ \text{shadow}=15 \\ \text{the shadow for the 18 fe}et\text{ tall is 15f}eet \end{gathered}

A house that is 12 feet tall casts a shadow that is 10 feet long. How long would the-example-1
User Roman Jaquez
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