Question

I have been getting messed up with these questions all day it would help a lot if you could explain one or two of my questions.

Answer 1

`\frac{y^{-7^{}}}{x^{7^{}}x^{8^{}}y^{-7^{}}}`

We can cancel y^-7 up with y^-7 down

Because in the division with power we subtract the power of the same base

So 7^-1/7^-1 = 7^(-1)-(-1) = 7^(-1+1) = the 7^(0) = 1

`\frac{1}{x^{7^{}}x^{8^{}}}`

Now let us add the powers of x because in multiplication we add the power of same base

x^7 * x^8 = x^(7 + 8) = x^15

The answer is 1/x^(15)

The first answer