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Michael Bray · Answer 1 · 2023-03-27T01:57:35+0000

Given

v = 81 km/h

t = 8.05 s

Procedure

Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt. This allows you to measure how fast velocity changes in meters per second squared (m/s^2).

$\begin{gathered} a=(\Delta v)/(\Delta t) \\ \end{gathered}$

But first we need to convert the km/h of the velocity into m/s

$\begin{gathered} 81\cdot\frac{\operatorname{km}}{\text{ h}}\cdot\frac{1000\text{ m}}{1\operatorname{km}}\cdot\frac{1\text{ h}}{3600\text{ s}} \\ 22.5\text{ m/s} \end{gathered}$
$\begin{gathered} a=(22.5m/s)/(8.05s) \\ a=2.8m/s^2 \end{gathered}$

The acceleration would be 2.8 m/s^2

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