The pressure value is given as,
![P=240\text{ kPa}](https://img.qammunity.org/2023/formulas/physics/college/xj1isk53o7860btqpvlotnpzm3fvt4orw3.png)
The value of the area is given as
![\begin{gathered} A=190cm^2 \\ A=190*10^(-4)m^2 \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/qj6q961epv1brtocq2vsxutw79c73q32gs.png)
Thus, total area for the four tires is,
![\begin{gathered} A^(\prime)=4* A \\ A^(\prime)=4*190*10^(-4) \\ A^(\prime)=760*10^(-4)m^2 \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/9qqxu9xvv04fwc38r3rzmrhibz78myaqtp.png)
The force exerted in terms of pressure and area is,
![\begin{gathered} F=P* A^(\prime) \\ F=240*10^3*760*10^(-4) \\ F=18240\text{ N} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/njb954wjywfttzwg70refqcds1zqy1gvh5.png)
According to the newton's law,
![F=mg](https://img.qammunity.org/2023/formulas/physics/college/x86s3sliv7jc1mzs9dn288p05klel6sw3t.png)
where g is the acceleration due to gravity.
Substituting the known values,
![\begin{gathered} 18240=m*9.8 \\ m=(18240)/(9.8) \\ m=1861.2\text{ kg} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/xhhbx1ssgnnitl331sjb34yz3ao2hadeq3.png)
Thus, the value of the mass of the car is 1861.2.