Two lines are perpendicular if and only if their slopes fulfil:

All of the equations are given in the form:

Then, the equation

has slope:

Plugging this in the perpendicular relation we have that:

this means that any perpendicular line to the one given has to have slope 3/5.
From the options given we notice that the only line that has this slope is:

Therefore, the perpendicular line is the last option.