Question

Can I get help with question 13 ? I don’t understand how to solve it

Answer 1

10.6 liters

Step-by-step explanation

What is given:

Density of the gasoline = 0.680 g/mL

Mass of the gasoline = 7.20 kg

What to find:

To find how large of a container, (volume) in liters needed to hold the gasoline.

Step-by-step solution:

Step 1: Convert the mass of gasoline from kg to g.

Conversion factor: 1 kg = 1000 g

So 7.20 kg = (7.20 kg/1 kg) x 1000 g = 7200 g

Step 2: Determine the volume in mL using the density equation.

`\begin{gathered} Density=(Mass)/(Volume) \\ \\ 0.680\text{ }g\text{/}mL=\frac{7200\text{ }g}{Volume\text{ }in\text{ }mL} \\ \\ Volume\text{ }in\text{ }mL=\frac{7200\text{ }g}{0.680\text{ }g\text{/}mL}=10588.24\text{ }mL \end{gathered}`

Step 3: Convert the volume in step 2 from mL to liters.

Conversion factor: 1000 mL = 1 L

So, 10588.24 mL = (10588.24 mL/1000 mL) x 1 L = 10.58824 liters

How large of a container, (volume) in liters needed to hold 7.20 kg of gasoline is approximately 10.6 liters