ANSWER and EXPLANATION
We have that CD is a bisector of AB. This means that it divides AB into two equal parts.
M lies on CD.
E is placed at a point equidistant to A and M. That means that the distance from A to E is the same as M to E
=> AM = BM
This is true since M lies on CD. That means it is equidistant from A and B.
=> CD = DM
This is true because M also lies at a point that is equidistant to point C and D.
=> EA = EM
This is true because as stated earlier, E is placed at a point equidistant to A and M.
=> EA < EB
This is true since E is closer to A than it is to B. So the distance from E to A is less than that from E to B.
=> AM < AB
This is true because AM is shorter than AB as the diagram shows.
=> AM > BM
This is false because we have shown that AM is in fact equal to BM.