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What happens to the period of a pendulum if the frequency is halved?

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The period of a pendulum is related to its frequency by the following formula:


T=(1)/(f)

If the frequency is halved we have:


T_2=(1)/((f)/(2))

Simplifying we get:


T_2=2((1)/(f))

The term inside the parenthesis is the original period, therefore:


T_2=2T

Therefore, if the frequency is halved the period is doubled.

User Michael Mikhjian
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