Given data
*The given height is h = 35 m
*The value of the acceleration due to gravity is g = 9.8 m/s^2
The formula for the speed of the lantern is given by the conservation of energy as
![\begin{gathered} U_p=U_k \\ mgh=(1)/(2)mv^2 \\ v=\sqrt[]{2gh} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/6wjmq97vrqgewfhr2e9cwbkryrkzzm7fpk.png)
Substitute the known values in the above expression as
![\begin{gathered} v=\sqrt[]{2*9.8*35} \\ =26.19\text{ m/s} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/mmd3ouk7vs6endcq0tuq9vk8hnbv1j67ji.png)
Hence, the speed of the lantern is v = 26.19 m/s