Question

What is the solution to the equation?

Answer 1

Explanation:

`\sqrt[3]{x+4}+\sqrt[3]{2x +8}=0\\\\\sqrt[3]{x+4}= -\sqrt[3]{2x + 8}\\\\(x +4)^{(1)/(3)}=-(2x+8)^{(1)/(3)}\\\\`

Take cube,

`[(x+4)^{(1)/(3)}]^(3) =- [(2x +8)^{(1)/(3)}^(3)]\\\\(x+4)^{3*(1)/(3)}=-(2x + 8)^{3*(1)/(3)}\\\\`

x + 4 = - (2x + 8)

x +4 = 2x *(-1) + 8 *(-1)

x+ 4 = -2x - 8

x +2x+4 = - 8

3x + 4 = - 8

3x = - 8 -4

3x = -12

x = -12/3

x = -4