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Find the equation of the line that passes through the point (6,14) and is parallel to the equation below. Y=4/3X-4

User LI Xuhong
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1 Answer

4 votes

Given

The point is given (6,14) and equation parallel to the equation passes through the point is given Y=4/3X-4.

Explanation

To determine the equation of line that passes through the point (6,14)

Use the general equation of line.


y-y_1=m(x-x_1)

Substitute the values.


y-14=m(x-6)

Now the slope of the line will be same as the slope of the equation of line which is parallel .

Because when two lines are parallel the slope of the lines are equal.


m=(4)/(3)

Then the equation formed is


\begin{gathered} y-14=(4)/(3)(x-6) \\ y=(4)/(3)x-8+14 \\ y=(4)/(3)x+6 \end{gathered}

Answer

Hence the equation of line formed is


y=(4)/(3)x+6

User LLS
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