5|x² - 3x| + 4y - 6
Replacing with x = 4 and y = 7, we get:
5|(4)² - 3(4)| + 4(7) - 6 =
First, we have to solve the absolute value and the multiplication.
Inside the absolute value, we have to solve first the quadratic and the multiplication.
= 5|16 - 12| + 28 - 6 =
= 5| 4 | + 28 - 6 =
= 5(4) + 28 - 6 =
= 20 + 28 - 6 =
= 42