Given the equation of the function:

The given function represents a parabola
We will make a complete square to find the coordinates of the vertex
The coefficient of x = 4
Half the coefficient of x = 2
Square it give = 4
So, we will add and subtract 4

Compare the last equation with the vertex form of the parabola

So, h = -2, k = -11
So, the answer will be the coordinates of the vertex = (-2, -11)