Question

8x+y=19
x=6y-16
Solve in system of equations

Answer 1

x=2, y=3

Explanation:

1. Substitute x=6y-16 into 8x+y=19

8(6y-16)+y=19

48y-128+y=19

2.Add like terms

49y-128=19

3. Add 128 on both sides to cancle out (-128)

49y=147

4.Divide 49 on both sides to cancle out 49

y=147/9

y=3

5. Substitute y value in 8x+y=19

8x+3=19

6. Subtract 3 on both sides to cancle it out

8x=16

7. Divde 16 by 8 to get your x value

x=16/8

x=2