To find the area of the polygon we can divide the figure into smaller figures like a rectangle and a triangle.
after we can make the mixed numbers as improper fractions to make them easier to work with

Find the area of the rectangle at the base using the formula

where l is b and w is a

Continue by finding the area of the triangle by the formula

in which b is tha base b and h is the height that is represented by the difference between 10 and a.

Add both areas together
