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14 votes
How many moles of a gas would occupy 11.4 L at 273K and 2.00 atm?

User Steve Lewis
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1 Answer

26 votes
26 votes

Answer:

1.02mol

Step-by-step explanation:

Using the general gas equation below;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

According to the information provided in this question,

P = 2.0 atm

V = 11.4L

T = 273K

n = ?

Using PV = nRT

n = PV/RT

n = 2 × 11.4/ 0.0821 × 273

n = 22.8/22.41

n = 1.017

n = 1.02mol

User David Sidarous
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