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Roger Cruz · Answer 1 · 2023-06-10T14:13:10+0000

Given that

$\begin{gathered} AB=AC=16\operatorname{cm} \\ BC=20\operatorname{cm} \\ BD=(BC)/(2)=\frac{20\operatorname{cm}}{2}=10\operatorname{cm} \\ CD=(BC)/(2)=\frac{20\operatorname{cm}}{2}=10\operatorname{cm} \\ AD=h \end{gathered}$

To calculate the height of the triangle, we will use the Pythagoras theorem

With the Pythagorean theorem, we will have

$\begin{gathered} \text{hypotenus}^2=\text{opposite}^2+\text{adjacent}^2 \\ \text{where,} \\ \text{HYPOTENUS}=AC=16\operatorname{cm} \\ \text{opposite}=DC=10\operatorname{cm} \\ \text{adjacent}=AD=h \end{gathered}$

By substituting the values, we will have

$\begin{gathered} \text{hypotenus}^2=\text{opposite}^2+\text{adjacent}^2 \\ 16^2=10^2+h^2 \\ 256=100+h^2 \\ \text{substract 100 from both sides} \\ 256-100=100-100+h^2 \\ 156=h^2 \\ \text{square root both sides} \\ \sqrt[]{h^2}=\sqrt[]{156} \\ h=\sqrt[]{4}*\sqrt[]{39} \\ h=2\sqrt[]{39} \\ or\text{ } \\ h=12.39\operatorname{cm}\approx to\text{ 1 d.p=} \\ h=12.5\operatorname{cm} \end{gathered}$

Therefore,

The height of the triangle is = 12.5 cm

AC=AB=16cm.BC=20cm. How do i find the height of the triangle?-example-1

AC=AB=16cm.BC=20cm. How do i find the height of the triangle?-example-2

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