The question provides the relationship as shown below:
![((1)/(4)+2)20=5+40](https://img.qammunity.org/2023/formulas/mathematics/college/udzg880n91iqhjv9lmu8y6en67mlo7lcir.png)
If we solve both sides individually, we have the left-hand side to give
![((1)/(4)+2)20=45](https://img.qammunity.org/2023/formulas/mathematics/college/72zqx8jz4pk9dz7tuo5pgbipi6jocmgxu7.png)
and the right-hand side to give
![5+40=45](https://img.qammunity.org/2023/formulas/mathematics/college/o3st5bobqsdvpehwy9r2ulokbfu6j3aze8.png)
Since both sides give the same result, we can attempt to manipulate the left-hand side of the equation with a common property we are familiar with: The Distributive Property.
The Distributive Property is written out as shown below:
![a(b+c)=(a\cdot b)+(a\cdot c)](https://img.qammunity.org/2023/formulas/mathematics/college/h1l2cppj7t81dr38zmewa4w574fanvk9c9.png)
Applying this rule to the left-hand side, we get:
![\begin{gathered} ((1)/(4)+2)20=(1)/(4)\cdot20+2\cdot20 \\ =5+40 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/l5gr45w18frn0b7zqivyis41nxbbkgaxzq.png)
This is the same expression present on the right-hand side of the equation.
Therefore, the property illustrated is the DISTRIBUTIVE PROPERTY.