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If a regular polygon has exteriorangles that measure approximately17.14° each, how many sides doesthe polygon have?

If a regular polygon has exteriorangles that measure approximately17.14° each, how-example-1

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To answer this question we will set and solve an equation.

Recall that the exterior angle of an n-gon has a measure of:


(360^(\circ))/(n).

Let n be the number of sides that the polygon that we are looking for has. Since the regular polygon exterior angles with a measure of approximately 17.14 degrees, then:


(360^(\circ))/(n)\approx17.14^(\circ).

Therefore:


n\approx(360^(\circ))/(17.14^(\circ))

Simplifying the above result we get:


n\approx21.

Answer: 21 sides.

User Rolando Urquiza
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