Given that:
- You have $200 to spend.
- The store sells all jeans for $25 and all dresses for $50.
- You want to take home 6 items of clothing.
Let be "j" the number of jeans and "d" the number of dresses you can buy so you use the whole $200 (not including the tax).
Set up this System of Equations using the data provided in the exercise:
![\begin{cases}j+d=6{} \\ 25j+50d={200}\end{cases}](https://img.qammunity.org/2023/formulas/mathematics/college/g60rsq25qvrgd4949lcindgs0vw65t7y8b.png)
You can follow these steps in order to solve the System of Equations using the Elimination Method:
1. You can multiply the first equation by -25:
![\begin{cases}-25j-25d={-150} \\ 25j+50d={200}\end{cases}](https://img.qammunity.org/2023/formulas/mathematics/college/il2zzkel1ovecpbxehney4nvkgc7oljdwk.png)
2. Add the equations:
![\begin{gathered} \begin{cases}-25j-25d={-150} \\ 25j+50d={200}\end{cases} \\ ------------ \\ 0j+25d=50 \\ 25d=50 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/fgviza5be8hhyvuafronz1qs19u2je79s0.png)
3. Solve for "d":
![\begin{gathered} d=(50)/(25) \\ \\ d=2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/e0kcg7941t7jlfoze66hpq4ptno1wh8qxe.png)
4. Substitute the value of "d" into the first original equation and solve for "j":
![\begin{gathered} j+(2)=6 \\ j=6-2 \\ j=4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/b9szjhapkkhtftii1k9rc7un4hmq4neobi.png)
Hence, the answer is: You can buy 2 dresses and 4 jeans.