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Consider a student’s work in determining the solution set of x > 2(y – 1)^2 – 2.

Test point: (2.25, 1.25)

x > 2(y – 1)^2 – 2

2.25 > 2(1.25 – 1)^2 – 2

2.25 > 2(0.25)^2 – 2

2.25 > 2(0.0625) – 2

2.25 > 0.125 – 2

2.25 > –1.875

Conclusion: The point (2.25, 1.25) satisfies the given inequality.

Solution set:



Which element, if any, shows an error in the student’s work?

There are no errors.
The conclusion statement is incorrect.
The graph of the solution set is incorrect.
The substitution of x and y values is incorrect.

Consider a student’s work in determining the solution set of x > 2(y – 1)^2 – 2. Test-example-1
User HelenM
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3.2k points

2 Answers

21 votes
21 votes

Answer:

Its C

Explanation:

User Vlazzle
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2.5k points
10 votes
10 votes

Answer:

  • C. The graph of the solution set is incorrect.

Explanation:

  • Solution is right, properly substituted x- and y-values, no mistakes.
  • Conclusion is right, the point within the solution set.
  • The only mistake is the graph, with > sign the line of the graph is not included into solution, therefore should be dotted.

There are no errors.

  • Incorrect (the graph)

The conclusion statement is incorrect.

  • Incorrect

The graph of the solution set is incorrect.

  • Correct (the line should be dotted)

The substitution of x and y values is incorrect.

  • Incorrect
Consider a student’s work in determining the solution set of x > 2(y – 1)^2 – 2. Test-example-1
User Miksiii
by
3.1k points