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I need help with this practice problem, I am struggling to solve It’s from my trigonometry prep guide

I need help with this practice problem, I am struggling to solve It’s from my trigonometry-example-1
User Ynimous
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1 Answer

2 votes

Answer:

Corey stepped 59.71 ft away

Step-by-step explanation:

The situation is sketched in the following diagram.

The distance from the foot of the tree is y and x for angles 41 and 68 degrees respectively.

Therefore, the distance Corey has to step away is y - x.

Now, from trigonometry, we know that


\tan (68^o)=\frac{\text{opposite}}{\text{adjacent}}
\Rightarrow\tan (68^o)=\frac{\text{8}0}{\text{x}}

We solve for x and get


\begin{gathered} \Rightarrow x\tan (68^o)=80 \\ \Rightarrow x=(80)/(\tan (68^o)) \end{gathered}

since tan (68) = 2.475.., the above becomes


x=(80)/(2.75\ldots)=32.32

Now, for angle 41 we have


\tan (41^o)=\frac{opposite}{\text{adjacent}}
\tan (41^o)=(80)/(y)

solving for y gives


y=(80)/(\tan (41^o))

since tan(41) = 0.869..., the above becomes


y=(80)/(0.869\ldots)
\Rightarrow y=92.0295\ldots

Therefore, the distance Corey has to step away from the tree to get a better view is (rounded to the nearest hundredth)


y-x=92.0295-32.322
\boxed{y-x=59.71.}

I need help with this practice problem, I am struggling to solve It’s from my trigonometry-example-1
User Maydin
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5.9k points