Given that we have the function f(x) = 5x-√8, it is equal to 13 at some value of x. This relation can be written in equation as
![5x-\sqrt[]{8}=13](https://img.qammunity.org/2023/formulas/mathematics/college/m6v8y6maxsz1dn740id521rlgb64k260gu.png)
Move √8 to the other side of the equation so that only the term with x will be left on the left-hand side. We have
![5x=13+\sqrt[]{8}](https://img.qammunity.org/2023/formulas/mathematics/college/t93ys6hnom4lcfjm8tuw8xl1sm0j5e5hcf.png)
Divide both sides by 5, we get
![\begin{gathered} (5x)/(5)=\frac{13+\sqrt[]{8}}{5} \\ x=\frac{13+\sqrt[]{8}}{5} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/98snlnvkztufywfb8f95ehrqozhcwydhlx.png)
The square root of 8 can be further simplified as
![\sqrt[]{8}=\sqrt[]{4\cdot2}=2\sqrt[]{2}](https://img.qammunity.org/2023/formulas/mathematics/college/da2va87pzuuxby7orlk9r7oknlp21vmt41.png)
Hence, the value of x can also be rewritten as
![x=\frac{13+2\sqrt[]{2}}{5}](https://img.qammunity.org/2023/formulas/mathematics/college/ypa4qplgb4arbema510u5janb0ioe4j8qw.png)
Thus, the value of x to satisfy f(x) = 13 when f(x)=5x -√8 is
![x=\frac{13+\sqrt[]{8}}{5}=\frac{13+2\sqrt[]{2}}{5}=(13)/(5)+\frac{2\sqrt[]{2}}{5}](https://img.qammunity.org/2023/formulas/mathematics/college/syuety9nygothlaz9sy0iw94asji1qyggr.png)