Question

On October 23, 2011, one U.S. dollar was worth 13.65 Mexican pesos.(a) On that date, how many pesos was 81.35 dollars worth?Round your answer to the nearest hundredth of a peso.pesos(b) On that date, how many dollars was 91.03 pesos worth?Round your answer to the nearest hundredth of a dollar.

Answer 1

We are given that

`\text{ \$}1=13.65\text{ }pesos`

a.

`\begin{gathered} \text{ \$}81.35=81.35*13.65\text{ }pesos \\ \\ \text{ \$}81.35=1110.43\text{ }pesos\text{ \lparen to the nearest hundredth\rparen} \end{gathered}`

b.

`\begin{gathered} 1\text{ }pesos=\text{ \$}(1)/(13.65) \\ \\ 91.03pesos=\text{ \$}(1)/(13.65)*91.03 \\ \\ 91.03pesos=\text{ \$}6.67\text{ \lparen to the nearest hundredth\rparen} \end{gathered}`