Question

What is the location of the vertex on the parabola defined by f(x) = 2x2 + 14x + 11 and in what direction does the parabola open?

Answer 1

Vertex of a parabola

The point where the parabola intersects its axis of symmetry is called the "vertex" and is the point where the parabola is most sharply curved.

The given function is,

`f(x)=2x^2+14x+11`

We will apply graphical method to obtain the solution to the vertex of the parabola

From the graph above, the vertex of the parabola is (- 3.5, - 13.5) which can also be represented into fraction as

`(-(7)/(2),-(27)/(2))`

And finally, the parabola opens upward.

Hence, the correct option is Option 2.