Question

On a coordinate plane, a line goes through (0, 3) and (3, negative 1). A point is at (negative 3, 2).

What is the equation of the line that is parallel to the given line and passes through the point (−3, 2)?

Answer 1

Explanation:

Slope of line passing through (0, 3) and (3, -1) = (-1-3)/(3-0) = -4/3

Slope of any parallel to the line is also -4/3.

Point-slope equation for line of slope -4/3 that passes through (-3, 2):

y-2 = (-4/3)(x+3)