Question

LOOK BELOW AT THE PICTURE

Answer 1

Explanation:

r₁ = radius of tabletop = 24 in

r₂ = radius of hole = 2 in

area of hole = πr₂² = 4π in²

area of tabletop = πr₁² - πr₂² = 576π - 4π = 572π ≈ 1796.08 in²

Answer 2

C. 1796.08
`in^2`

Explanation:

Area of circle is
`\pi r^2`, r is the radius

remember radius is from the center to the edge, so it is half the diameter

now we need to find the area of the large circle (table) minus the small circle (hole)

the radius of the large circle is 48/2 which is 24

the area is
`\pi 24^2` replacing r in the formula with 24, the radius. Using 3.14 as pi, the answer is 1808.64

the radius of the small circle is 4/2 which is 2

the area is
`\pi 2^2` so the calculated value would be 12.56

now subtract the area of the hole (small circle) from the area of the table (large circle)

1808.64 - 12.56 = 1796.08

and there's your answer

hope that helps, lmk if it doesn't :)