Question

in rst the measure of ∠J=90° the measure of ∠H=69° and Hl=88 feet. find the length of JH to the nearest tenth of a foot

Answer 1

From the information provided, we can construct the following triangle;

The measure of angle J is 90 degrees, the measure of angle H is 69 degrees and line HI measures 88 feet. Therefore to calculate line JH;

`\begin{gathered} \cos \theta=(adj)/(hyp) \\ \cos 69=(JH)/(88) \\ \text{Cross multiply and you'll have;} \\ 88*\cos 69=JH \\ 88*0.35836794\ldots=JH \\ 31.5363\ldots=JH \\ JH\approx31.5ft \end{gathered}`

The answer is 31.5 feet (rounded to the nearest tenth of a foot