Question

PLZ HELP !!!!!!!Solve for the value of x and y
68
(4x - 2)
30

Answer 1

x = 10, y = 112

Explanation:

4x - 2 + 30 and 68 are vertical angles and are congruent , then

4x - 2 + 30 = 68

4x + 28 = 68 ( subtract 28 from both sides )

4x = 40 ( divide both sides by 4 )

x = 10

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y and 68 lie on a straight line and sum to 180° , then

y + 68 = 180 ( subtract 68 from both sides )

y = 112

Answer 2

Answer: 10

Explanation:

Simplifying

68 = 4x + -2 + 30

Reorder the terms:

68 = -2 + 30 + 4x

Combine like terms: -2 + 30 = 28

68 = 28 + 4x

Solving

68 = 28 + 4x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x' to each side of the equation.

68 + -4x = 28 + 4x + -4x

Combine like terms: 4x + -4x = 0

68 + -4x = 28 + 0

68 + -4x = 28

Add '-68' to each side of the equation.

68 + -68 + -4x = 28 + -68

Combine like terms: 68 + -68 = 0

0 + -4x = 28 + -68

-4x = 28 + -68

Combine like terms: 28 + -68 = -40

-4x = -40

Divide each side by '-4'.

x = 10

Simplifying

x = 10