Given:
Slope of line is m = -1/4 and passes through point (-2,6).
Step-by-step explanation:
The general equation of line with slope m and passing through point (x_1,y_1) is,
![y-y_1=m(x-x_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/csobd57zth7rh9k4hz9amldzpq2owf0z4j.png)
Determine the equation of line passing through point (-2,6) and have slope of -1/4.
![\begin{gathered} y-6=-(1)/(4)(x-(-2)) \\ y-6=(-1)/(4)\cdot x-(1)/(4)\cdot2 \\ y=-(x)/(4)-(1)/(2)+6 \\ y=-(x)/(4)+(11)/(2) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/i73fihzksm97dev9omewzmpequh0ip3d59.png)
So equation of line is,
y = -x/4 + 11/2