Question

Solve the equation 42+7c - 5 = 0 using the quadratic formula

Answer 1

The equation is:

`4c^2+7c-5=0`

so we can use the cuadratic equation so:

`\begin{gathered} c=\frac{-b\pm\sqrt[]{b^2-4(a)(c^(\prime))}}{2(a)} \\ \text{where} \\ a=4 \\ b=7 \\ c^(\prime)=-5 \end{gathered}`

So if we replace in the equation we will have:

`c=\frac{-7\pm\sqrt[]{7^2-4(4)(-5)}}{2(4)}`

So we simplify to solve the problem so:

`c=\frac{-7\pm\sqrt[]{129}}{8}`