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The diameter of a circle is 20 kilometers. What is the angle measure of an arc bounding a sector with area 10pi square kilometers?Give the exact answer in simplest form. ____°. (pi, fraction,)

The diameter of a circle is 20 kilometers. What is the angle measure of an arc bounding-example-1
User Shreddd
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1 Answer

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The area of a circular sector is given by:


A=(1)/(4)\cdot\pi\cdot d^2\cdot(\theta)/(360)

Where:

π ≈ 3.14159

d = diameter of the circle

θ = angle of the circular sector

In our problem we have that:


\begin{gathered} A=10\cdot\pi\cdot km^2 \\ d=20\operatorname{km} \end{gathered}

And we need to find the value of the angle θ. So in order to solve the problem, we replace the given data in the formula of above:


\begin{gathered} A=(1)/(4)\cdot\pi\cdot d^2\cdot(\theta)/(360^(\circ)) \\ 10\cdot\pi\cdot km^2=(1)/(4)\cdot\pi\cdot(20\operatorname{km})^2\cdot(\theta)/(360^(\circ)) \end{gathered}

And now we solve for θ:


\begin{gathered} 10\cdot\pi\cdot km^2=(1)/(4)\cdot\pi\cdot400\cdot km^2\cdot(\theta)/(360^(\circ)) \\ 10=100\cdot(\theta)/(360^(\circ)) \\ 360^(\circ)\cdot(10)/(100)=\theta \\ \theta=36^(\circ) \end{gathered}

So the answer is that the angle of the circular sector is: 36°

User Bnahin
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