The area of a circular sector is given by:

Where:
π ≈ 3.14159
d = diameter of the circle
θ = angle of the circular sector
In our problem we have that:
![\begin{gathered} A=10\cdot\pi\cdot km^2 \\ d=20\operatorname{km} \end{gathered}]()
And we need to find the value of the angle θ. So in order to solve the problem, we replace the given data in the formula of above:
![\begin{gathered} A=(1)/(4)\cdot\pi\cdot d^2\cdot(\theta)/(360^(\circ)) \\ 10\cdot\pi\cdot km^2=(1)/(4)\cdot\pi\cdot(20\operatorname{km})^2\cdot(\theta)/(360^(\circ)) \end{gathered}]()
And now we solve for θ:

So the answer is that the angle of the circular sector is: 36°