Answer:
Explanation:
r=4, w=3, b=2, g=1, t=(4+3+2+1)=10
9) P(r or g)=4/10+1/10=5/10= 1/2
10) P(r or b)=4/10+2/10=6/10= 3/5
11) P(!b)=P(r or w or g)=4/10+3/10+1/10=8/10= 4/5
12) There are six numbers and only one six, P(6)= 1/6
13) The only even numbers less than 5 are 2 and four so
P(e<5)=2/6= 1/3
14) The primes on a die are 2,3,5 so three primes out of six numbers
P(!)=3/6= 1/2
15) 2,3,4,6 are multiples of 2 and three
P(2n or 3n)=4/6= 2/3
16) We want a one half probability so
P(W)=(3+x)/(3+4+2+x)=1/2
(3+x)/(9+x)=1/2
2(3+x)=9+x
6+2x=9+x
x=3
So 3 white marbles have to be added.
17) (3+x)/(9+x)=2/3
3(3+x)=2(9+x)
9+3x=18+2x
x=9
So nine whites need to be added.