Question

A typical adult ear has a surface area of 2.61× 10-3 m². The sound intensity during a normal conversation is about 2.65 x 10-6 W/m² at the listener's ear. Assume that the sound strikes the surface of the ear perpendicularly. How much power is intercepted by the ear?

Answer 1

6.9 x 10^-9 W

Explanation:

Given:

Area (A) = 2.61× 10^-3 m²

Intensity (I) = 2.65 x 10^-6 W/m²

We can determine the power by the following formula:

`\begin{gathered} P=A\cdot I \\ \\ \text{ We replacing:} \\ \\ P=2.61\cdot10^(-3)\cdot2.65\cdot10^(-6) \\ \\ P=6.9\cdot10^(-9)\text{ W} \end{gathered}`

The power is 6.9 x 10^-9 W