Answer:
B) y = 2x
Step-by-step explanation:
We were given the following details:
The straight line passes through the origin; it passes through the point (0, 0)
The straight line passes through the point (1, 2)

The general equation of a straight line is given by:

We will obtain the equation of the straight line as shown below:
I. Obtain the slope of the straight line

The slope of the straight line is 2
II. Obtain the y-intercept
Method 1:
The y-intercept refers to the point where the straight line crosses the y-axis.
In this case, the straight line crosses the y-axis at the origin (0, 0). This implies that:

Method 2:
Using the point-slope equation:

Therefore, the answer is B (y = 2x)