Question

A car has a velocity of 21.3 m/s. It then accelerates at a uniform rate of 3.6 m/s per second for the next 5.0 seconds. What distance does the car cover during this time? Round to 4 decimal places if necessary

Answer 1

Step-by-step explanation

U uniformly accelerated motion is the one in which the acceleration of the particle throughout the motion is uniform,the formula to find the distance is as follows:

`\begin{gathered} x=v_ot+(1)/(2)at^2 \\ where \\ v_o\text{ is the initial velocity} \\ t\text{ is the time} \\ a\text{ is the acceleration} \end{gathered}`

so

Step 1

a)let

`\begin{gathered} v_o=21.3\text{ }(m)/(s) \\ a=3.6(m)/(s^2) \\ t=5\text{ s} \end{gathered}`

b) now,replace in the formula and calculate

`\begin{gathered} x=v_(o)t+(1)/(2)at^(2) \\ x=21.3(m)/(s)*5s+(1)/(2)3.6(m)/(s^2)*(5\text{ s\rparen}^2 \\ x=106.5\text{ m}+45\text{ m} \\ x=151.5\text{ m} \end{gathered}`

therefore, the answer is 151.5 meters

I hope this helps you