Question

What is an equation for the line that passes through points (2.-3) and (1, 2)? (+ 3) = -5(x - 2) b. (y - 3) = 5(x ! 2) (y - 3) = -5(.x + 2) d. (+3) = S(x - 2)​

Answer 1

A. y + 3 = -5(x - 2)

Explanation:

The slope is:

2 - (-3) / 1 - 2 = 5 / -1 = -5.

Then, put it in point slope form (which was
`(y - y1) = m(x-x1)` where m is the slope, and (x1, y1) is the coordinate point it gives you. You can use m = -5, x1 = 2 and y1 = -3.)

y + 3 = -5(x - 2)