Given:
Given a rectangle with coordinates A(-5, 6), B(3, 6), C(3, -1) and D(-5, -1).
Required: Area of rectangle ABCD
Step-by-step explanation:
First, find the length and width of the rectangle.
![\begin{gathered} \text{ Length, }DC=√((-5-3)^2+(-1-(-1))^2) \\ =√((-8)^2+0^2) \\ =8 \\ \text{ Width, }BC=√((3-3)^2+(6-(-1))^2) \\ =√(0^2+7^2) \\ =7 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/2b4gcaf3jlt2ocd4ipjuzg38sudpw6xs8o.png)
The are of the rectangle is
![\begin{gathered} A=\text{Length}*\text{Width} \\ =8*7 \\ =56 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/bigcyu0tubxthrfb9ojhhezmdkfpcee226.png)
Option C is correct.
Final Answer: Rectangle ABCD has area 56 square units.