Question

A chemistry student experiments on producing table salt by reacting pure sodium cubes with confined chlorine gas. If the procedure is successful, how much salt is produced with 160 g of chlorine gas used? *

with solution pls

Answer 1

Answer: 263 grams of salt is produced.

Step-by-step explanation:

To calculate the moles :

`\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}`

`\text{Moles of} Cl_2=(160g)/(71g/mol)=2.25moles`

The balanced chemical reaction is:

`2Na(s)+Cl_2(g)\rightarrow 2NaCl(s)`

According to stoichiometry :

1 mole of
`Cl_2` produce = 2 moles of
`NaCl`

Thus 2.25 moles of
`Cl_2` will produce =
`(2)/(1)* 2.25=4.50moles` of
`NaCl`

Mass of
`NaCl=moles* {\text {Molar mass}}=4.50moles* 58.5g/mol=263g`

Thus 263 grams of salt is produced.