Question

Passing through (-2, 8) and PERPENDICULAR to y = 2x + 5

Answer 1

the equation of the line is,

y = 2x + 5

the slope of the line is m = 2

the slope of the line perpendicular to y = 2x + 5 is ,

m = -1/2

it is passing through (-2,8)

so the equation of the line is

`y-8=(-(1)/(2))(x-(-2))`
`\begin{gathered} y-8=-(1)/(2)x-1 \\ y=-(1)/(2)x+7 \end{gathered}`

thus the equation of the line is,

y = -1/2 x + 7