Question

A spinner is divided into many sections of equal size. Some sections are red, some are blue, and the remaining are green. The probability of the arrow landing on a section colored red is 12/20. The probability of the arrow landing on a section colored blue is 6/20. What is the probability of the arrow landing on a green-colored section? ​

Answer 1

`(2)/(20)`

Explanation:

We have 3 sections.

1. 
   `(12)/(20)`
2. 
   `(6)/(20)`
3. 
   `(x)/(20)`

Since we only have 3 sections, we can add red and blue, and subtract
`(20)/(20)`

`(12)/(20) + (6)/(20) = (18)/(20)`

Subtract:

`(20)/(20)-(18)/(20) = (2)/(20)`

Answer 2

2/20

Explanation:

12 + 6 is 18 so then your remaining would be 2 so your answer should be 2/20!