Question

Determine which function has a greater initial value and explain how you know.

function 1: y=2(1/3)^x​

Answer 1

Answer - Function 2

Function 1 - y = 2x (1/3)^x x = 0 =2*0*1 = 0

Function 2 have the value for 3 for x = 0

Function 2 is greater