Let x, y and z denote the weighs of car X, car Y and car Z, respectively.
We know that car X weighs 136 more than car Z, this can be express by the equation:
![x=z+136](https://img.qammunity.org/2023/formulas/mathematics/college/78s469z40j8nbtqgjsu7jurbl367kei7dw.png)
We also know that Y weighs 117 pounds more than car Z, this can be express as:
![y=z+117](https://img.qammunity.org/2023/formulas/mathematics/college/fb4qyawoeygkilg3gsjp0isrth6mhtzxid.png)
Finally, we know that the total weight of all the cars is 9439, then we have:
![x+y+z=9439](https://img.qammunity.org/2023/formulas/mathematics/college/f8gv8427xasd0p21nqmq18l4ryp5emhw99.png)
Hence, we have the system of the equations:
![\begin{gathered} x=z+136 \\ y=z+117 \\ z+y+z=9439 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/9qpv7240k81clfxmjt7hufjjx4vgi339h5.png)
To solve the system we can plug the values of x and y, given in the first two equations, in the last equation; then we have:
![\begin{gathered} z+136+z+117+z=9439 \\ 3z=9439-136-117 \\ 3z=9186 \\ z=(9186)/(3) \\ z=3062 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/9n40g4tbmry0346vkd8zrwulgygi7lrg3r.png)
Now that we have the value of z we plug it in the first two equations to find x and y:
![\begin{gathered} x=3062+136=3198 \\ y=3062+117=3179 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/9kitgnsvi60o29t9h0o338zxufbi7hm6co.png)
Therefore, car X weighs 3198 pound, car Y weighs 3179 pounds and car Z weighs 3062 pounds.