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Find the axis of symmetry of the graph y = x2 + 8x + 16.

User Zahirabbas
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The axis of simetry of a parabola is the vertical line that cross the vertex of the parabola.

So, we need to find the x-value of the vertex:


\begin{gathered} \text{The general equation of a parabola is:} \\ y=ax^2+bx+c \\ \text{The x-value of the vertex is:} \\ x_v=-(b)/(2a) \end{gathered}

So, in this case a=1 and b=8:


x_v=-(8)/(2\cdot1)=-4_{}

The axis of simetry is x=-4.

User Gooid
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