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Solve the polynomial in standard form1) y=(x-3)^2-3(x-4)
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Solve the polynomial in standard form1) y=(x-3)^2-3(x-4)

User Kolen
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1 Answer

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y=\mleft(x-3\mright)^2-3\mleft(x-4\mright)
\begin{gathered} y=x^2-6x+9-3x+12 \\ \end{gathered}

we reduce the equal terms and we obtain the answer is


y=x^2-9x+21

User Grettke
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